(6分之5+900 0.8755-12分之5)÷...

终极至尊SB49E
-0.6) ] ÷1
+(0.6-0.6)] ÷
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根据问他()题库系统分析,
试题“0.+0.+0.312...”,相似的试题还有:
+++++=()×()
▲+▲+▲+□+□=24,□+□+▲+▲+▲+▲+▲=32,▲=(),□=().
++++=24++++++=32=_____,=_____.Fraction to Decimal Conversion chart, halves, thirds, quarters, fifths, sixths, sevenths, eighths, ninths, tenths, elevenths, twelfths, sixteenths, thirty-seconths
Fractions and Decimals Conversion Chart
Note: decimals marked with * are NOT EXACT
and have been rounded to 6 decimal places
0.333333 *
0.666667 *
0.166667 *
0.333333 *
0.666667 *
0.833333 *
0.142857 *
0.285714 *
0.428571 *
0.571428 *
0.714285 *
0.857143 *
0.111111 *
0.222222 *
0.333333 *
0.444444 *
0.555555 *
0.666667 *
0.777778 *
0.888889 *
0.090909 *
0.181818 *
0.272727 *
0.363636 *
0.454545 *
0.545454 *
0.636364 *
0.727273 *
0.818182 *
0.909091 *
0.083333 *
0.166667 *
0.333333 *
0.416667 *
0.583333 *
0.666667 *
0.833333 *
0.916667 *
Note: decimals marked with * are NOT EXACT
and have been rounded to 6 decimal places
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>>>解比例。(1)1.5:12=6:x(2)x:=:2(3)=(4)x:=0.875:5(5):=x:0.5(..
(1)1.5:12=6:x
(2)x:=:2
(4)x:=0.875:5
(5):=x:0.5
题型:计算题难度:中档来源:同步题
(1)1.5:12=6:x&&&&&&&&&&&&& 1.5x=72&&&&&&&&&&&&&&&&&&x=48
(2)x:=:2&&&&&&&&&&&&&&2x=&&&&&&&&&&&&&&& x=
(3)=&&&&&&&&& 1.3x=78&&&&&&&&&&&&& x=60
(4)x:=0.875:5&&&&&&&&&&& &&& 5x=3&&&&&&&&&&&&&&&&& x=0.6
(5):=x:0.5&&&&&&&& &&&&& x=&&&&&&&&&&&&&&&&&& x=
(6)=&&&&&&&&& 0.03x=0.06&&&&&&&&&&&&& && x=2
马上分享给同学
据魔方格专家权威分析,试题“解比例。(1)1.5:12=6:x(2)x:=:2(3)=(4)x:=0.875:5(5):=x:0.5(..”主要考查你对&&解比例,比例的应用题&&等考点的理解。关于这些考点的“档案”如下:
现在没空?点击收藏,以后再看。
因为篇幅有限,只列出部分考点,详细请访问。
解比例,比例的应用题
解比例:求比例中的未知项,叫做解比例。根据比例的基本性质(即交叉相乘),如果已知比例中的任何三项,就可以求出这个比例中的另外一个未知项。求比例中的未知项,叫做解比例。解比例是利用比例的基本性质:在比例中,两个外项的积等于两个内项的积。再转化成方程。比例应用题:是小学六年级奥数中的一个重要内容。它既是整数应用题的继续与深化,又是学习更多数学知识的重要基础,同时,这类题又有着自身的特点和解题的规律。在处理几个量的倍比关系时,比例应用题与分数百分数应用题间有很多相似之处,但利用比例处理问题要方便灵活得多。&要解决好此类问题,须注意灵活运用画线段示意图等手段,多角度、多侧面思考问题。在解题过程中,要善于掌握对应、假设、转化等多种解题方法,在寻找正确的解题方法的同时,不断地开拓解题思路。用比例方法解应用题的一般步骤:
发现相似题
与“解比例。(1)1.5:12=6:x(2)x:=:2(3)=(4)x:=0.875:5(5):=x:0.5(..”考查相似的试题有:
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