经验1735 米
在线时间201 小时
版本V8.1.6.0.MAACNDI
机型小米手机5
签到次数50
MIUI版本V8.1.6.0.MAACNDI
本帖最后由 壹笑而过 于
21:16 编辑
不知道为什么昨天的帖子找不到了！算了在写次！& && & （本帖纯属自己编写，工具都是网络大神们的，先想他们致敬）
ONE S 可恶的五行红字！进两天新进了部手机 HTC ONE S 呵呵，心情很激动！
泡坛子，学习，研究，官解，Root…我想这是现在年轻人拿的手机后都想尝试的！
与其知道很冒险……我就是这样一个人！杯具出现了。
官解后，迫切的想刷新ROM.在刷recovery的时候线掉了。
HTC& &&&This build is for
& & development purposes
only Do not distribute outside of
HTC without HTC's written permission.
Failure to comply may lead to legal action
就这五行红字。还好工程模式能进去，但是recovery进不去，重启，显示五行红字！
真的傻了~:dizzy::dizzy:
彻底的傻了~:'(:'(:'(
怎么捣鼓就是不行。结果搞的没有电了，彻底黑了。心凉透了。
送卖家那里，他们更水。搞不了，需要返厂。
送HTC专修，说是字库坏了，需要500大洋…黑心啊！
在坛子里看见一句话：如果你死得不能再死，
通常只要手机能进入fastboot usb，
也就是电脑上的驱动装好了，就能救！
& && && && && && && && && && && && && && &好了，静下心了，看我怎么解决的（花费了，我两天时间,摸索……）
前提：手机必须官方解锁为UNLOCKED或者为S-OFF！
一，确保你机子还有电，能进工程模式！（这时候可能关不了机，强制也不行。电会耗完，
& &所以，插上USB数据线，在电脑上充一会电）
& &进入工程模式（电源键+音量下键）选择FASTBOOT&&必须有显示：FASTBOOT USB。
1.jpg (112.32 KB, 下载次数: 9)
二，引导手机启动。（这次启动并不是说手机现在恢复了，关机开机还会进红字界面。）
& &我们用r1-villec-superboot工具，解压后打开文件夹双击里面install-superboot-windows.bat
& &命令自动进行。手机会进去红字界面，但是能越过去，重新启动。（这时候，是不是心情好了许多，
& &死了几天的手机活了。)好了别高兴了，插上充电器，美美的充满电，主要还在后面！
三，刷了N多recovery都进不去，我们就避开它~直接刷机！找了很长时间才找到！伪官方直刷版工具和包
现在手机处于开机状态。准备工作：手机一定要开启调试模式，并安装驱动完毕！
图解，第一步输入F进入Bootloader[也可以手工进入，下音量+开机即可]
3.jpg (114.81 KB, 下载次数: 77)
手机会进入如下图的Bootloader界面，并且显示FASTBOOT USB
然后在工具中选择P进入刷机模式
4.jpg (76.24 KB, 下载次数: 5)
刷机模式如下图所示！黑底白字！
5.jpg (94.86 KB, 下载次数: 0)
进入刷机模式后选择R刷入ROM！如下图所示，刷机时请勿断开USB线
6.jpg (115.62 KB, 下载次数: 3)
在这里我要很严重的说明！包下好后不要乱动！更不要把ROM拖出去！必须在根目录下！
选择后会直接进入刷机。这时候手机会有10~20分钟的假死状态！（五行红字界面）
千万别乱动！耐心等待！耐心等待！耐心等待！这时候，就是我们鉴证奇迹的时刻！
(6.02 MB, 下载次数: 7493)
22:58 上传
点击文件名下载附件
通过这个引导手机开启
下载积分: 经验 -1 米
(309.74 KB, 下载次数: 2277)
23:30 上传
点击文件名下载附件
通过这个重新刷入伪官ROM
下载积分: 经验 -1 米
(198 Bytes, 下载次数: 1416)
00:05 上传
点击文件名下载附件
下载积分: 经验 -1 米
这个是ROM+工具包！
& && && && &（115网盘不提供大众下载功能了）汗！
& && && && & 账号@密码：
通过几位机油的贴身体验！刷机前一定先
看看自己是S几的！？MIUI只支持S4！
一·只要机子能进工程模式！
& && && &进入工程模式（电源键+音量下键）选择FASTBOOT&&
& && && && && &&&必须有显示：FASTBOOT USB上有图
二·用免recovery工具刷入官方ROOM或是
& && && &伪官方ROOM
& && && & 机子处于解锁状态无所谓，上锁不上锁都行！
& && && && & （等待以后S-OFF教程吧！）
& &&&忘各位杯具了的机油不要走冤枉路了~
& &&&实在不懂的问我吧~
分享到微信朋友圈
打开微信，点击底部的“发现”，使用 “扫一扫” 即可将网页分享到我的朋友圈。
已有&7&人评分
我手机开机就是5行红字，但是能开机，没问.
MIUI 因你更精彩！
刷回官方REC就没这几个字啦，还搞这么麻烦.
MIUI这次太贱了
精品文章^_^
感谢分享经验^_^
经验1735 米
在线时间201 小时
版本V8.1.6.0.MAACNDI
机型小米手机5
签到次数50
MIUI版本V8.1.6.0.MAACNDI
只是个人经验！有不对之处 希望原谅!!& &也是拿出来大家分享一下！
经验5476 米
在线时间643 小时
版本V8.2.5.0.MADCNDL
积分 6555, 距离下一级还需 13445 积分
积分 6555, 距离下一级还需 13445 积分
机型小米Note2
签到次数104
MIUI版本V8.2.5.0.MADCNDL
通过手机发布
其实不需要刷rom的，有第三方recovery和原recovery可以刷的只要把recovery和boot替换到miui教程里直接就能刷好re的
经验1735 米
在线时间201 小时
版本V8.1.6.0.MAACNDI
机型小米手机5
签到次数50
MIUI版本V8.1.6.0.MAACNDI
recovery?我快刷了N多次了！换什么版本都是一样&&卡在红字拿！
有个版本的recovery我还真的能进~但是刷到一会的时候Android小机器人倒地上死了！（刷机失败）
当场真的把我气笑了~~~
经验5476 米
在线时间643 小时
版本V8.2.5.0.MADCNDL
积分 6555, 距离下一级还需 13445 积分
积分 6555, 距离下一级还需 13445 积分
机型小米Note2
签到次数104
MIUI版本V8.2.5.0.MADCNDL
通过手机发布
壹笑而过 发表于
回复 cisten 的帖子
recovery?我快刷了N多次了！换什么版本都是一样&&卡在红字拿！
不知道你刷的哪个rom,s3现在无论用哪个re都刷不了miui的
经验1735 米
在线时间201 小时
版本V8.1.6.0.MAACNDI
机型小米手机5
签到次数50
MIUI版本V8.1.6.0.MAACNDI
本帖最后由 壹笑而过 于
11:06 编辑
当然&&我没有刷MIUI的ROM！&&:D& && &
我另部手机I9000用的MIUIROM
经验402 米
在线时间4 小时
版本V7.1.5.0.KXDCNCK
积分 408, 距离下一级还需 92 积分
积分 408, 距离下一级还需 92 积分
机型小米手机3/4 WCDMA版
签到次数35
MIUI版本V7.1.5.0.KXDCNCK
如果不能显示FASTBOOT USB意味着什么呢？我是S3的机器，按照MIUI官方的刷机方法刷了，也按照这个方法救了，结果一直显示HBOOT，没法显示FASTBOOT USB，现在发到深圳去了，说是要换字库，而且还不知道能不能救。。。。。
经验1735 米
在线时间201 小时
版本V8.1.6.0.MAACNDI
机型小米手机5
签到次数50
MIUI版本V8.1.6.0.MAACNDI
我刚刚开始&&也是这样说的！ 黑你…回来要很多大洋的！
只要你能进工程模式&&就行！&&没有连上USB证明你驱动没有装好！
经验402 米
在线时间4 小时
版本V7.1.5.0.KXDCNCK
积分 408, 距离下一级还需 92 积分
积分 408, 距离下一级还需 92 积分
机型小米手机3/4 WCDMA版
签到次数35
MIUI版本V7.1.5.0.KXDCNCK
啊？我都送修了，黑得很，说的是字库坏了，有两个版本的字库，其中一个版本不能救，另外一个版本能救。。。。晕死了。现在还没有报价，说的是就算修也得等20多天。。。。。把我郁闷惨了。好端端的刷机，怎么会刷坏字库，简直不懂了。还有就是MIUI的刷机教程，也不提醒一下哪些机器不能刷。。。。。
经验402 米
在线时间4 小时
版本V7.1.5.0.KXDCNCK
积分 408, 距离下一级还需 92 积分
积分 408, 距离下一级还需 92 积分
机型小米手机3/4 WCDMA版
签到次数35
MIUI版本V7.1.5.0.KXDCNCK
壹笑而过 发表于
回复 草田木0 的帖子
我刚刚开始&&也是这样说的！ 黑你…回来要很多大洋的！
驱动没有装好是指电脑上的驱动没有装好吗？但是我在网上下了很多驱动也不行呀？！
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京ICP备号 | 京公网安备34号 | 京ICP证110507号& “先通读下面的短文，然后根据短文内容和所给...”习题详情
170位同学学习过此题，做题成功率72.9%
先通读下面的短文，然后根据短文内容和所给首字母，在空格内填入一个合适的词，使短文意思完整。所填单词必须在答题卡标有题号的横线上完整写出。Do you know March 14th is International Police Day. The traffic police is just one group. No matter if it is in summer& o【小题& 1】or&1【小题& 2】 weekday& in winter, a holiday or a w【小题& 3】watch&2【小题& 4】show&, we can see policemen w【小题& 5】millions&3【小题& 6】solve& the traffic at the crossroads on the main roads.There are over1.9 million policemen in our country. It is a day for us to s【小题& 7】peace&4【小题& 8】deal& our respect for police, the people who keep m【小题& 9】needs&5【小题& 10】well& of families safe. Other police have different duties. Some are firefighters. Some watch out for bad guys and s　&6　& crimes. Others keep the p　&7　&. Special police d　&8　& with unexpected events. A good special policeman n　&9　& a strong body as w　&10　& as rich knowledge and many skills. He has to learn laws, science, shooting, driving and climbing.To keep people safe, Chinese police put their lives at risk. Since 1990 more than 15,000 policemen have lost their lives. Another 20,000 were hurt in doing jobs.
本题难度：较难
题型：填空题&|&来源：2012-江苏省无锡市华仕初三中考模拟（5月）英语试卷
分析与解答
习题“先通读下面的短文，然后根据短文内容和所给首字母，在空格内填入一个合适的词，使短文意思完整。所填单词必须在答题卡标有题号的横线上完整写出。Do you know March 14th is Internation...”的分析与解答如下所示：
【小题& 1】考查连词：无论是夏天还是冬天，用or&&【小题& 2】考查名词：无论是假期还是工作日： weekday 【小题& 3】我们都能看见警察注视着交通：watch&&【小题& 4】考查词组：show respect for尊敬【小题& 5】考查数词：millions of成千上万的【小题& 6】考查动词：solve crimes处理犯罪行为【小题& 7】考查名词：keep the peace维持和平【小题& 8】考查动词：deal with处理【小题& 9】考查动词;一个好警察需要强壮的身体：主语是A good special policeman 谓语是needs&&【小题& 10】考查词组：as well as而且
找到答案了，赞一个
如发现试题中存在任何错误，请及时纠错告诉我们，谢谢你的支持！
先通读下面的短文，然后根据短文内容和所给首字母，在空格内填入一个合适的词，使短文意思完整。所填单词必须在答题卡标有题号的横线上完整写出。Do you know March 14th is Intern...
错误类型：
习题内容残缺不全
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分析解答有文字标点错误
分析解答结构混乱
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“先通读下面的短文，然后根据短文内容和所给...”的最新评论
欢迎来到乐乐题库，查看习题“先通读下面的短文，然后根据短文内容和所给首字母，在空格内填入一个合适的词，使短文意思完整。所填单词必须在答题卡标有题号的横线上完整写出。Do you know March 14th is International Police Day. The traffic police is just one group. No matter if it is in summer o____1____ in winter, a holiday or a w____2____, we can see policemen w____3____ the traffic at the crossroads on the main roads.There are over1.9 million policemen in our country. It is a day for us to s____4____ our respect for police, the people who keep m____5____ of families safe. Other police have different duties. Some are firefighters. Some watch out for bad guys and s____6____ crimes. Others keep the p____7____. Special police d____8____ with unexpected events. A good special policeman n____9____ a strong body as w____10____ as rich knowledge and many skills. He has to learn laws, science, shooting, driving and climbing.To keep people safe, Chinese police put their lives at risk. Since 1990 more than 15,000 policemen have lost their lives. Another 20,000 were hurt in doing jobs.”的答案、考点梳理，并查找与习题“先通读下面的短文，然后根据短文内容和所给首字母，在空格内填入一个合适的词，使短文意思完整。所填单词必须在答题卡标有题号的横线上完整写出。Do you know March 14th is International Police Day. The traffic police is just one group. No matter if it is in summer o____1____ in winter, a holiday or a w____2____, we can see policemen w____3____ the traffic at the crossroads on the main roads.There are over1.9 million policemen in our country. It is a day for us to s____4____ our respect for police, the people who keep m____5____ of families safe. Other police have different duties. Some are firefighters. Some watch out for bad guys and s____6____ crimes. Others keep the p____7____. Special police d____8____ with unexpected events. A good special policeman n____9____ a strong body as w____10____ as rich knowledge and many skills. He has to learn laws, science, shooting, driving and climbing.To keep people safe, Chinese police put their lives at risk. Since 1990 more than 15,000 policemen have lost their lives. Another 20,000 were hurt in doing jobs.”相似的习题。thirteen equals one_百度文库
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定制HR最喜欢的简历
你可能喜欢One-to-one relationships | Django documentation | Django
The web framework for perfectionists with deadlines.
One-to-one relationships
To define a one-to-one relationship, use .
In this example, a Place optionally can be a Restaurant:
from django.db import models
class Place(models.Model):
name = models.CharField(max_length=50)
address = models.CharField(max_length=80)
def __str__(self):
# __unicode__ on Python 2
return &%s the place& % self.name
class Restaurant(models.Model):
place = models.OneToOneField(Place, primary_key=True)
serves_hot_dogs = models.BooleanField(default=False)
serves_pizza = models.BooleanField(default=False)
def __str__(self):
# __unicode__ on Python 2
return &%s the restaurant& % self.place.name
class Waiter(models.Model):
restaurant = models.ForeignKey(Restaurant)
name = models.CharField(max_length=50)
def __str__(self):
# __unicode__ on Python 2
return &%s the waiter at %s& % (self.name, self.restaurant)
What follows are examples of operations that can be performed using the Python
API facilities.
Create a couple of Places:
&&& p1 = Place(name='Demon Dogs', address='944 W. Fullerton')
&&& p1.save()
&&& p2 = Place(name='Ace Hardware', address='1013 N. Ashland')
&&& p2.save()
Create a Restaurant. Pass the ID of the “parent” object as this object’s ID:
&&& r = Restaurant(place=p1, serves_hot_dogs=True, serves_pizza=False)
&&& r.save()
A Restaurant can access its place:
&&& r.place
&Place: Demon Dogs the place&
A Place can access its restaurant, if available:
&&& p1.restaurant
&Restaurant: Demon Dogs the restaurant&
p2 doesn’t have an associated restaurant:
&&& from django.core.exceptions import ObjectDoesNotExist
p2.restaurant
&&& except ObjectDoesNotExist:
print(&There is no restaurant here.&)
There is no restaurant here.
You can also use hasattr to avoid the need for exception catching:
&&& hasattr(p2, 'restaurant')
Set the place using assignment notation. Because place is the primary key on
Restaurant, the save will create a new restaurant:
&&& r.place = p2
&&& r.save()
&&& p2.restaurant
&Restaurant: Ace Hardware the restaurant&
&&& r.place
&Place: Ace Hardware the place&
Set the place back again, using assignment in the reverse direction:
&&& p1.restaurant = r
&&& p1.restaurant
&Restaurant: Demon Dogs the restaurant&
Note that you must save an object before it can be assigned to a one-to-one
relationship. For example, creating a Restaurant with unsaved Place
raises ValueError:
&&& p3 = Place(name='Demon Dogs', address='944 W. Fullerton')
&&& Restaurant.objects.create(place=p3, serves_hot_dogs=True, serves_pizza=False)
Traceback (most recent call last):
ValueError: save() prohibited to prevent data loss due to unsaved related object 'place'.
Changed in Django 1.8.4: Previously, saving an object with unsaved related objects did not raise an
error and could result in silent data loss. In 1.8-1.8.3, unsaved model
instances couldn’t be assigned to related fields, but this restriction was
removed to allow easier usage of in-memory models.
Restaurant.objects.all() just returns the Restaurants, not the Places.
that there are two restaurants - Ace Hardware the Restaurant was created in the
call to r.place = p2:
&&& Restaurant.objects.all()
[&Restaurant: Demon Dogs the restaurant&, &Restaurant: Ace Hardware the restaurant&]
Place.objects.all() returns all Places, regardless of whether they have
Restaurants:
&&& Place.objects.order_by('name')
[&Place: Ace Hardware the place&, &Place: Demon Dogs the place&]
You can query the models using :
&&& Restaurant.objects.get(place=p1)
&Restaurant: Demon Dogs the restaurant&
&&& Restaurant.objects.get(place__pk=1)
&Restaurant: Demon Dogs the restaurant&
&&& Restaurant.objects.filter(place__name__startswith=&Demon&)
[&Restaurant: Demon Dogs the restaurant&]
&&& Restaurant.objects.exclude(place__address__contains=&Ashland&)
[&Restaurant: Demon Dogs the restaurant&]
This of course works in reverse:
&&& Place.objects.get(pk=1)
&Place: Demon Dogs the place&
&&& Place.objects.get(restaurant__place=p1)
&Place: Demon Dogs the place&
&&& Place.objects.get(restaurant=r)
&Place: Demon Dogs the place&
&&& Place.objects.get(restaurant__place__name__startswith=&Demon&)
&Place: Demon Dogs the place&
Add a Waiter to the Restaurant:
&&& w = r.waiter_set.create(name='Joe')
&&& w.save()
&Waiter: Joe the waiter at Demon Dogs the restaurant&
Query the waiters:
&&& Waiter.objects.filter(restaurant__place=p1)
[&Waiter: Joe the waiter at Demon Dogs the restaurant&]
&&& Waiter.objects.filter(restaurant__place__name__startswith=&Demon&)
[&Waiter: Joe the waiter at Demon Dogs the restaurant&]
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Hosting byMathwords: One-to-One Function
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One-to-One Function
for which every
of the function corresponds to exactly one element
of the . One-to-one is often written 1-1.
is a function if it passes the . It is a 1-1
if it passes both the vertical line test and the . Another way of testing whether a function is 1-1 is given
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Mathwords: Terms and Formulas from Algebra I to Calculus
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