If Q is an odd number and the median xlof Q consecutive integers is 120,

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GMAT 数学 GMAT 数学讲义 arithmetic progression
等差数列 geometric
progression
等比数列 set
集合 数学词汇 term
子集 sequence
序列中的项
1. 数学符号 inclusive
包含序列的首末项 exclusive
不包含序列的首末项
等于: ≡ equal to, the same as, is 5.排列组合与概率
> more than combination
组合 < less than probability,possibility
概率 ≥ no more than
加: + add A to B, plus, sum of A and B, total
减: - minus, less, difference, subtract A common division
from B common factor
乘: × multiply,product composite number
合数(质数与1 以外的自然数)
除: ÷ A divided by B,A divided into B, consecutive integer
A divisible by B digit
绝对值: |…| absolute value dividend
平方: X 2
square divide
除以 divisor
立方: X 3
cube divisible by 可整除的 evenly divisible
可整除的 even number
开平方: square root factor
因子 3 integer
开立方: cube root irrational 无理数
// parallel to least common multiple
最小公倍数
垂直: ⊥ perpendicular to multiple 公倍数
2. 数字前缀 natural number
自然数 negative number
1:uni, mono, nonzero 非零
2: bi, du, di odd number 奇数
3: tri, ter positive number
4: tera, quad prime factor
5: penta, quint prime number
6: hex, sex quotient
7: sept,hapta rational
8: oct real number 实数
9: enn remainder 余数
10: dec, deka whole number 整数
3. 方程 units’digit 个位数 tens’digit 十位数
方程 solution
解 hundreds' digit
4. 4.数列和集合 2-digit number 两位数 1 GMAT 数学 maximum 最大值 minimum 最小值
7.单利复利和价格 multipl
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If Q is an odd number and the median of Q consecutive integers is 120, what is the largest of these integers?
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题目:假设Q是奇数,并且Q个连续整数的中位数是120,问这些整数中最大的数是什么。解:Q是奇数,则这些连续整数的中位数120就是数列中处于最中间的数,因此120左右两边分别有(Q-1)/2个数,数列中最大的数就是120+(Q-1)/2。
如果对题目有任何的疑惑,欢迎在这里提出来,大家会帮你解答的哦~
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medianMedian value of array
SyntaxM = median(A) M = median(A,dim) M = median(___,nanflag) DescriptionM = median() returns
the median value of A.If A is a vector, then median(A) returns
the median value of A.If A is a nonempty matrix, then median(A) treats
the columns of A as vectors and returns a row vector
of median values.If A is an empty 0-by-0 matrix, median(A) returns NaN.If A is a multidimensional array,
then median(A) treats the values along the first
array dimension whose size does not equal 1 as
vectors. The size of this dimension becomes 1 while
the sizes of all other dimensions remain the same.median computes natively in the numeric class
of A, such that class(M) = class(A).M = median(,) returns
the median of elements along dimension dim. For
example, if A is a matrix, then median(A,2) is
a column vector containing the median value of each row.M = median(___,) optionally
specifies whether to include or omit NaN values
in the median calculation for any of the previous syntaxes. For example, median(A,'omitnan') ignores
all NaN values in A.Examples
Define a 4-by-3 matrix.A = [0 1 1; 2 3 2; 1 3 2; 4 2 2]
Find the median value of each column.M = median(A)
For each column, the median value is the mean of the middle two numbers in sorted order.
Define a 2-by-3 matrix.A = [0 1 1; 2 3 2]
Find the median value of each row.M = median(A,2)
For each row, the median value is the middle number in sorted order.
Create a 1-by-3-by-4 array of integers between 1 and 10.A = gallery('integerdata',10,[1,3,4],1)
A(:,:,1) =
A(:,:,2) =
A(:,:,3) =
A(:,:,4) =
Find the median values of this 3-D array along the second dimension.M = median(A)
M(:,:,1) =
M(:,:,2) =
M(:,:,3) =
M(:,:,4) =
This operation produces a 1-by-1-by-4 array by computing the median of the three values along the second dimension. The size of the second dimension is reduced to 1.Compute the median along the first dimension of A.M = median(A,1);
isequal(A,M)
This command returns the same array as A because the size of the first dimension is 1.
Define a 1-by-4 vector of 8-bit integers.A = int8(1:4)
1&4 int8 row vector
Compute the median value.M = median(A),
M is the mean of the middle two numbers in sorted order returned as an 8-bit integer.Create a vector and compute its median, excluding NaN values.A = [1.77 -0.005 3.98 -2.95 NaN 0.34 NaN 0.19];
M = median(A,'omitnan')
Input ArgumentsMore AboutAlgorithmsFor ordinal categorical arrays, MATLAB® interprets the median
of an even number of elements as follows:If the number of categories between
the middle two values is ...Then the median
zero (values are from consecutive categories)larger of the two middle values
an odd numbervalue from category occurring midway between the two middle
an even numbervalue from larger of the two categories occurring midway between
the two middle values
See Also |
Introduced before R2006a
You clicked a link that corresponds to this MATLAB command:
Run the command by entering it in the MATLAB Command Window.
Web browsers do not support MATLAB commands.
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If Q is an odd number and the median of Q consecutive integers is 120, what is the largest of these integers?答案: (Q-1)÷2+120
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思路:因为该数列是个consecutive数列,则公差是1那么,欲求数列中最大的数,只需要知道:A:这个数列的中数,即120, & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & B:最大数是中数的后几位数,-----------------------------运算:已知这个数列有Q个数,那么最大数比中数大(Q-1)/2比如:数列1,2,3,4,5中,中数是3,那么,最大数5比中数3就大了(5-1)/2,楼主要记住这点,所以,题中的中数是120,则最大数为120+(Q-1)/2这个题其实就考了在连续等差数列中,中数和最大数的关系表达,主要是要抓住连续等差数列中公差为1 的特点
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思路如下:序列 & &个数 & 最大数 1 & & & & & & 1 & & & & 120 &2 & & & & & & 3 & & & & 121 &3 & & & & & & 5 & & & & 122 &... &m & & & & & Q & & & & & ?显然 Q =2*m-1 &即m=(Q+1)/2归纳如下: 120=120+(1-1) & & & & & 121=120+(2-1) & & & & & 。。。 & & & & & MAX=120+(m-1)=(Q-1)/2+120
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到时候可以列举几个数看看 找找规律
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