若k∈{4,5,6,7},且sin(kπ/2-a)=-已知sina cosa,cos(kπ/2-a)=cosa,则k的值是 求过程

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/etc/nginx/nginx.conf.对任何k∈z都有sin(α+kπ)=cos(α+π+kπ)则角α的值是
cos(α+π+kπ)=-cos(α+kπ)sin(α+kπ)=-cos(α+kπ)k为偶数时:sinα=-cosα , α=3π/4k为奇数时:
-sinα=cosα,
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