9 k^52/5=5^5-5a a^5-99=5
an 7-an 4=m=444容易有误差
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扫描下载二维码若a=（2√2+√5）/（√5-√2）,求a^5-7a^4+5a^3-7a^2+11a+13 的值要求写出明细.
esJI14WW91
a=（2√2+√5）/（√5-√2）,
a=（2√2+√5）（√2+√5）^2/[（√5-√2）（√2+√5）]=(9+3√5)/3=3+√5a^5-7a^4+5a^3-7a^2+11a+13 =(a^5-6a^4+9a^3) -(a^4 +4a^3+4a^2)-3a^2+12a-12+25=a^3(a-3)^2-a^2(a-2)^2+3a(a...
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a =（2√2+√5）/（√5-√2）=（2√2+√5）*（√5+√2）/ 3=（5+4+3√10）/ 3= 3+√10所以 a-3=√10，(a-3)^2=10，从而a^2-6a-1=0，故a^5-7a^4+5a^3-7a^2+11a+13 =a^3(a^2-6a-1)-a^2(a^2-6a-1)-8(a^2-6a-1)-37...
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